4y^2-17y+18=0

Solution for 4y^2-17y+18=0 equation:

4y^2-17y+18=0

a = 4; b = -17; c = +18;
Δ = b2-4ac
Δ = -172-4·4·18
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-1}{2*4}=\frac{16}{8}
=2
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+1}{2*4}=\frac{18}{8}
=2+1/4
$